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2x^2-52x+330=0
a = 2; b = -52; c = +330;
Δ = b2-4ac
Δ = -522-4·2·330
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-8}{2*2}=\frac{44}{4} =11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+8}{2*2}=\frac{60}{4} =15 $
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